In figure, AB AC, D is the point in the interior of ABC such that
Given: AB = AC, D is the point in the interior of ?ABC such that ?DBC = ?DCB.
To Prove: AD bisects ?BAC of ?ABC.
Proof: In ?DBC,
? ?DBC = ?DCB ...(1) | Given
? DB = DC ...(2)
| Sides opposite to equal angles of a triangle are equal
In ?ABC,
? AB = AC | Given
? ?ABC = ?ACB
? ?ABC = ?ACB ...(3)
| Angles opposite to equal sides of a triangle are equal
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